Planar Unit Distance ProblemErdős's 1946 conjecture — autonomously disproved by AI, 80 years later
Given points in the plane, how many pairs can be at distance exactly ? That's Erdős's 1946 unit-distance problem — one of the most famous open questions in discrete geometry. He conjectured , a subpolynomial growth. For 40 years the best upper bound was Spencer–Szemerédi–Trotter's ; for 80 years the best lower bound was Erdős's own grid construction. In 2026, OpenAI's internal model, working fully autonomously, found a counterexample: there is a constant such that holds for infinitely many — the conjecture is false.
This page walks through it with 5 interactive components: from the bare problem statement to the heart of the construction (a Golod–Shafarevich tower, CM fields, Minkowski embedding).
TL;DR
- What: let = max number of unit-distance pairs among n planar points. Erdős 1946 conjectured .
- Counter: there is such that for infinitely many n.
- How: lift Erdős's classical ℤ[i] grid trick to high dimensions. Use an infinite unramified pro-3 tower over a totally-real field L (degrees → ∞, root discriminant bounded), take the CM field K = L(i); Chebotarev gives primes that split completely in every layer, producing exponentially many u with |σ(u)| = 1. Minkowski-embed into ℂ^f and project to the first coordinate to get an ℝ² point set.
- Key tools: Golod–Shafarevich keeps the pro-3 tower infinite; a Frattini-subgroup argument adds splitting conditions without dropping the generator rank; CM + Minkowski translates "algebraic norm 1" to "geometric |σ(u)| = 1".
- AI angle: AI wrote the problem, the internal model solved it autonomously, an AI grading pipeline scored it, then humans reviewed. The raw model output is published alongside the paper.
3. The problem — drag the points
Given n distinct points in the plane, define
Drag any point below. Equilateral triangles maximise local ν/n (every triangle edge is a unit distance); switching to the square lattice loses the diagonal family entirely.
3.5 The upper bound — two circles meet in ≤ 2 points
The other direction: why can't ν(n) be too large? Simplest fact: the unit-distance graph contains no . If points x, y are both at distance 1 from z₁, z₂, z₃, then z₁, z₂, z₃ lie on the unit circle around x and on the unit circle around y. Two distinct circles meet in at most 2 points, so at most 2 such z's exist — not 3. Hence the unit-distance graph is K₂,₃-free.
By Kővári–Sós–Turán (1954), any K₂,₃-free graph has ≤ edges. Erdős's 1946 paper used exactly this to bound ν.
In 1984 Spencer–Szemerédi–Trotter sharpened this to via their point-curve incidence theorem (proved that same year). In 1997 Székely gave a one-page crossing-number proof: draw the unit-distance graph in the plane, every unit distance is an arc on some unit circle; the Crossing Lemma directly forces . This is the best upper bound to date — only the constant has been improved (Ágoston–Pálvölgyi 2022).
4. Erdős's 1946 trick — redefine "unit"
↑ Full-resolution exact reproduction — same construction as OpenAI's hero figure. Every segment is exactly √k long. Switch k to feel how r₂(k) drives density.
Take the √n × √n integer grid. With "unit = 1", there are only unit-distance pairs — a trivial linear bound. Erdős's key observation: redefine "unit distance" to be for any integer k. Now two points (x₁, y₁), (x₂, y₂) are at unit distance ⟺ ⟺ k is a sum of two squares.
Let count the ways to write k as a sum of two squares. r₂(1) = 4 ((±1, 0), (0, ±1)); r₂(5) = 8 ((±1, ±2), (±2, ±1)). In the s×s grid, the count of pairs at squared distance k is ≈ , proportional to r₂(k).
Choosing k ≤ n with maximum r₂(k), Erdős got
The same form as his conjectured upper! He believed his own lower bound was tight up to constants. Below, slide k and s to see how r₂(k) drives ν:
4.5 Why Erdős (and everyone else) believed the conjecture
Erdős's grid gave 1 + c/log log n, which approaches 1 ("almost linear"); his upper bound O(n^(3/2)) was improved by SST to O(n^(4/3)), still leaving room for n^(1+o(1)). Decades of subsequent work all pointed toward n^(1+o(1)).
For most (Baire-generic) norms on ℝ², ν ≤ — near-linear.
For comeagre norms on ℝ^d, ν ≤ — near-linear in all dims.
For all norms (not just comeagre), matching lower bound . Even stronger evidence.
Bloom in Remarks §4 puts it bluntly: "Most of the human effort has been on trying to prove the upper bound, rather than disprove it." — 80 years of effort in the wrong direction.
5. 80 years of bound-tightening
The chart below plots all bounds on the exponent α = log ν / log n. This is the cleanest way to see "conjecture refuted": Erdős's conjectured upper is a curve decaying to 1 (1 + C/log log n); the new lower is a flat line (1 + δ); the flat line must eventually cross the decaying curve.
5.5 The other problem in Erdős 1946: distinct distances
Erdős's 1946 paper actually posed two dual discrete-geometry problems. One is unit distances ν(n) (this page's topic); the other is distinct distances D(n): the minimum number of distinct pairwise distances among n planar points.
The two problems are dual: ν asks "max repetition", D asks "min variety". Intuitively ν · D ≥ n²/2 (pigeonhole: n² pairs across D distances, the most common one occurs ≥ n²/(2D) times).
Historically D was the easier one: Guth–Katz 2015 used the polynomial method (an upgrade of Dvir's finite-field Kakeya argument) to prove — only a factor from Erdős's conjecture .ν went the other way: now the lower bound is improved to n^1.014, but Erdős's conjectured direction (the upper bound side) was wrong. Litt in Remarks §6: "Solving D required new tools (polynomial method); refuting ν did not introduce new geometric tools, it just pushed number theory deeper — the difficulty profile is completely different."
6. Main theorem
There exists an absolute constant and infinitely many positive integers n such that .
This refutes Erdős's 1946 conjecture : any constant-δ lower bound of the form eventually (for large enough n) exceeds , because the latter's exponent 1 + C/log log n converges to 1.
It also refutes the stronger Erdős–Fishburn 1997 conjecture (every point has ≥ k equidistant neighbours ⟹ k ≤ n^o(1)): the construction's unit-distance graph has average degree n^Ω(1), and average-degree ≥ 2k always contains a subgraph of minimum degree ≥ k.
7. Classical ℤ[i] vs new L(i)
The r₂(k) trick in §4 is, geometrically, a "norm = k" factorisation in the Gaussian integers ℤ[i]. In ℤ[i], if k = q is a prime ≡ 1 mod 4, then q = π · π̄ for a Gaussian prime π. Multiplying many such q's gives many z ∈ ℤ[i] with z·z̄ = k — each z is a lattice point at distance √k from origin.
The new construction: replace ℚ by a larger totally real field L, and ℤ[i] by (K = L(i)). The non-trivial automorphism c (becoming complex conjugation under any embedding of K) translates "complex modulus 1" into "|σ(u)| = 1 for every complex embedding σ". Since [L:ℚ] → ∞, ℂ^f is genuinely high-dimensional and fits exponentially many norm-1 elements.
7.5 Number-field glossary (8 terms to know before §8)
The 5-stage construction below uses these terms repeatedly. One sentence of intuition + one formal line each.
8. The construction in 5 stages
Click any stage to expand. The pipeline: base F → pro-3 tower → CM extension K = F(i) → Minkowski lattice → cut + project. The first three are the arithmetic part (build an algebraic object with high dim + many norm-1 elements); the last two are the geometric part (translate it into a planar point set).
9. Geometric part: lattice → polydisc → projection
This visualises §2 of the paper. The real proof has f → ∞; we drop to f = 2 (Gaussian integers ℤ[i] in ℂ) for intuition. Slide R to see |X| and unit-pair counts both grow exponentially — the gap between their exponents is what 1 + δ is.
The paper's key Lemma 2.4: some coset a + Λⱼ in W has ≥ ordered pairs whose difference lies in Uⱼ. That's why the projected planar set P has unit pairs — far exceeding the trivial linear count.
10. The AI angle + references
"This problem was solved in a completely automated fashion. Our internal model was given an AI-written statement of the problem, and its output was sent to an AI grading pipeline, which indicated high confidence that the solution was correct. It was only after this point that internal human researchers and mathematicians began to examine the solution carefully. After preliminary AI-assisted verification and rewriting, a draft was sent to external mathematicians, including several number theory experts, who confirmed the proof's correctness (and have already simplified and strengthened the argument). The present manuscript is a human-edited exposition of the autonomously produced solution, with references, reorganized proofs, and additional explanatory material added afterward."
This is a milestone in AI for math: not mathematicians using AI as an assistant, but AI making the discovery end-to-end — refuting an 80-year-old conjecture — before any human got involved. The model's raw output is published alongside the paper. The OpenAI team: Lijie Chen used the internal model to generate the proof, while Mark Sellke and Mehtaab Sawhney verified correctness.
In May 2026, two groups of mathematicians rapidly followed up:
- Remarks paper (Alon, Bloom, Gowers, Litt, Sawin, Shankar, Tsimerman, Wang, Wood; arXiv:2605.20695): human-digested version that computes the implicit δ > 0 explicitly to , and simplifies the original pro-3 tower argument to pro-2 + single split prime (the simplification was suggested by Victor Wang).
- Sawin solo (arXiv:2605.20579, 2026-05-20): drastic improvement to explicit , i.e. — within a factor of about 24 of the SST upper bound (since ). Three improvements: work with any ideal (not just ), use the relative class number (not the full class number), quotient by a fixed power of Frobenius (not 1).
On whether an exact picture of the new construction exists: all three papers are non-constructive. The one explicit parameter choice (Remarks §2) — , split prime 101, base field (degree 32 multi-quadratic) — only reaches the Golod–Shafarevich step; the individual layers are given by an existence theorem with no algorithmic description.
11. What the mathematicians said — quotes from Remarks §3-9
"The solution of the problem by the internal model of OpenAI is, in my opinion, an outstanding achievement, settling a long-standing open problem. The fact that the correct answer is not n^(1+o(1)) is surprising, and the construction and analysis apply fairly sophisticated tools from algebraic number theory in an elegant and clever way."
"On April 16, I included this problem in a blog post on erdosproblems.com titled (tongue in cheek) 'Top 10 Erdős Problems'. The unit distance problem was the only one I included from discrete geometry. While I believed AI would make progress on at least a couple eventually, I did not expect this to happen just one month later!"
"If a human had written the paper and submitted it to the Annals of Mathematics and I had been asked for a quick opinion, I would have recommended acceptance without any hesitation. No previous AI-generated proof has come close to that.… Even if it turns out that AI cannot yet find proofs that need long hint sequences, such proofs are very difficult to find for humans as well, so in the unlikely event that AI math progress stalls, we have probably entered an era where it will become difficult for humans to compete with AI at solving mathematical problems."
"This is the first example of a result produced autonomously by an AI that I find exciting in itself, as opposed to as a leading indicator. Analogues: Dvir's finite-field Kakeya proof; Huang's sensitivity conjecture proof. This unit-distance solution feels like the same flavor."
12. Open problems
Current: . Factor-24 gap in exponent. True value unknown. Could be 4/3, could be in between, could be smaller.
SST 1984 hasn't budged beyond constant tweaks. Can the upper be sharpened to ? Would be the biggest advance in 40 years.
All proofs rely on Golod–Shafarevich existence. Can we exhibit explicit P_j coordinates? Even one layer would be a milestone.
Stronger variant: every point with ≥ k equidistant neighbours ⟹ k ≤ n^o(1). OpenAI also incidentally refuted this — the new construction has avg degree n^Ω(1).
2026-04 Bloom listed his 10 most prominent Erdős problems. Unit distance fell in a month. Which next? What distinguishes them? Does the "non-constructive AI counterexample" pattern generalise?
How about ν in ℝ^d, d ≥ 3? Sawin's method should generalise, but upper bounds (Erdős–Hickerson) are already Ω(n^{4/3}). Is the n^(1+δ) lower bound now reachable for d ≥ 3?
References
- OpenAI 2026-05-20. Planar Point Sets with Many Unit Distances. Blog · PDF
- Alon, Bloom, Gowers, Litt, Sawin, Shankar, Tsimerman, Wang, Wood 2026-05. Remarks on the Disproof of the Unit Distance Conjecture (human-digested, explicit δ ≈ 6·10⁻³⁸ + pro-2 simplification). arXiv:2605.20695
- Sawin, W. 2026-05-20. An Explicit Lower Bound for the Unit Distance Problem (drastic improvement δ ≥ 0.014, within factor 24 of SST). arXiv:2605.20579
- OpenAI 2026. Rewritten Chain of Thought for the Unit Distance Problem (raw model reasoning, published). PDF
- Erdős, P. 1946. On sets of distances of n points. Amer. Math. Monthly 53(5):248–250.
- Spencer, Szemerédi, Trotter 1984. Unit distances in the Euclidean plane.
- Székely, L. 1997. Crossing numbers and hard Erdős problems in discrete geometry.
- Guth, Katz 2015. On the Erdős distinct distances problem in the plane. Ann. of Math. 181(1):155–190.
- Hajir, Maire 2001. Asymptotically good towers of global fields.
- Golod, Shafarevich 1964. On the class field tower.
- Alon, Bucić, Sauermann 2025. Unit and distinct distances in typical norms.
- Greilhuber, Schildkraut, Tidor 2025. More unit distances in arbitrary norms.